The figure shows the amount of water in two rectangular tanks, N and P, at first. Liam poured
14 of the water from N into P to fill it to the top, without overflowing.
- How much water was there in Tank N at first?
- Liam then poured all the water from Tank P into Tank N. 1760 cm3 of water overflowed from Tank N. What was the height of Tank N?
(a)
Volume of water to fill Tank P
= 16 x 13 x 13
= 2704 cm
3
14 of volume of water in Tank N at first = 2704 cm
3
44 of volume of water in Tank N at first = 4 x 2704 = 10816 cm
3 Volume of water in Tank N at first = 10816 cm
3 Volume of water in Tank P at first
= 16 x 13 x 16
= 3328 cm
3 Total volume of water in Tank N and Tank P
= 10816 + 3328
= 14144 cm
3 Final volume of water in Tank N after 1760 cm
3 of water overflowed
= 14144 - 1760
= 12384 cm
3 Base area of Tank N
= 18 x 16
= 288 cm
2 Height of Tank N
= 12384 ÷ 288
= 43 cm
Answer(s): (a) 10816 cm
2 ; (b) 43 cm