The figure shows the amount of water in two rectangular tanks, L and M, at first. John poured
15 of the water from L into M to fill it to the top, without overflowing.
- How much water was there in Tank L at first?
- John then poured all the water from Tank M into Tank L. 3360 cm3 of water overflowed from Tank L. What was the height of Tank L?
(a)
Volume of water to fill Tank M
= 14 x 12 x 14
= 2352 cm
3
15 of volume of water in Tank L at first = 2352 cm
3
55 of volume of water in Tank L at first = 5 x 2352 = 11760 cm
3 Volume of water in Tank L at first = 11760 cm
3 Volume of water in Tank M at first
= 14 x 12 x 16
= 2688 cm
3 Total volume of water in Tank L and Tank M
= 11760 + 2688
= 14448 cm
3 Final volume of water in Tank L after 3360 cm
3 of water overflowed
= 14448 - 3360
= 11088 cm
3 Base area of Tank L
= 18 x 14
= 252 cm
2 Height of Tank L
= 11088 ÷ 252
= 44 cm
Answer(s): (a) 11760 cm
2 ; (b) 44 cm