The figure shows the amount of water in two rectangular tanks, J and K, at first. Tommy poured
13 of the water from J into K to fill it to the top, without overflowing.
- How much water was there in Tank J at first?
- Tommy then poured all the water from Tank K into Tank J. 2200 cm3 of water overflowed from Tank J. What was the height of Tank J?
(a)
Volume of water to fill Tank K
= 20 x 16 x 16
= 5120 cm
3
13 of volume of water in Tank J at first = 5120 cm
3
33 of volume of water in Tank J at first = 3 x 5120 = 15360 cm
3 Volume of water in Tank J at first = 15360 cm
3 Volume of water in Tank K at first
= 20 x 16 x 18
= 5760 cm
3 Total volume of water in Tank J and Tank K
= 15360 + 5760
= 21120 cm
3 Final volume of water in Tank J after 2200 cm
3 of water overflowed
= 21120 - 2200
= 18920 cm
3 Base area of Tank J
= 22 x 20
= 440 cm
2 Height of Tank J
= 18920 ÷ 440
= 43 cm
Answer(s): (a) 15360 cm
2 ; (b) 43 cm