The figure shows the amount of water in two rectangular tanks, U and V, at first. George poured ¹₃ of the water from U into V to fill it to the top, without overflowing.

1. How much water was there in Tank U at first?
2. George then poured all the water from Tank V into Tank U. 3040 cm³ of water overflowed from Tank U. What was the height of Tank U?

(a)
Volume of water to fill Tank V
= 19 x 16 x 15
= 4560 cm<sup>3

1</sup>₃ of volume of water in Tank U at first = 4560 cm^3  
3₃ of volume of water in Tank U at first = 3 x 4560 = 13680 cm³

Volume of water in Tank U at first = 13680 cm³

Volume of water in Tank V at first
= 19 x 16 x 19
= 5776 cm³

Total volume of water in Tank U and Tank V 
= 13680 + 5776
= 19456 cm³

Final volume of water in Tank U after 3040 cm³ of water overflowed
= 19456 - 3040
= 16416 cm³

Base area of Tank U
= 24 x 19
= 456 cm²

Height of Tank U
= 16416 ÷ 456 
= 36 cm

Answer(s): (a) 13680 cm² ; (b) 36 cm