The figure shows the amount of water in two rectangular tanks, R and S, at first. Tim poured
14 of the water from R into S to fill it to the top, without overflowing.
- How much water was there in Tank R at first?
- Tim then poured all the water from Tank S into Tank R. 5776 cm3 of water overflowed from Tank R. What was the height of Tank R?
(a)
Volume of water to fill Tank S
= 19 x 16 x 17
= 5168 cm
3
14 of volume of water in Tank R at first = 5168 cm
3
44 of volume of water in Tank R at first = 4 x 5168 = 20672 cm
3 Volume of water in Tank R at first = 20672 cm
3 Volume of water in Tank S at first
= 19 x 16 x 20
= 6080 cm
3 Total volume of water in Tank R and Tank S
= 20672 + 6080
= 26752 cm
3 Final volume of water in Tank R after 5776 cm
3 of water overflowed
= 26752 - 5776
= 20976 cm
3 Base area of Tank R
= 24 x 19
= 456 cm
2 Height of Tank R
= 20976 ÷ 456
= 46 cm
Answer(s): (a) 20672 cm
2 ; (b) 46 cm