The figure shows the amount of water in two rectangular tanks, S and T, at first. Lee poured
15 of the water from S into T to fill it to the top, without overflowing.
- How much water was there in Tank S at first?
- Lee then poured all the water from Tank T into Tank S. 3648 cm3 of water overflowed from Tank S. What was the height of Tank S?
(a)
Volume of water to fill Tank T
= 16 x 14 x 13
= 2912 cm
3
15 of volume of water in Tank S at first = 2912 cm
3
55 of volume of water in Tank S at first = 5 x 2912 = 14560 cm
3 Volume of water in Tank S at first = 14560 cm
3 Volume of water in Tank T at first
= 16 x 14 x 17
= 3808 cm
3 Total volume of water in Tank S and Tank T
= 14560 + 3808
= 18368 cm
3 Final volume of water in Tank S after 3648 cm
3 of water overflowed
= 18368 - 3648
= 14720 cm
3 Base area of Tank S
= 20 x 16
= 320 cm
2 Height of Tank S
= 14720 ÷ 320
= 46 cm
Answer(s): (a) 14560 cm
2 ; (b) 46 cm