The figure shows the amount of water in two rectangular tanks, N and P, at first. Elijah poured
14 of the water from N into P to fill it to the top, without overflowing.
- How much water was there in Tank N at first?
- Elijah then poured all the water from Tank P into Tank N. 513 cm3 of water overflowed from Tank N. What was the height of Tank N?
(a)
Volume of water to fill Tank P
= 19 x 15 x 13
= 3705 cm
3
14 of volume of water in Tank N at first = 3705 cm
3
44 of volume of water in Tank N at first = 4 x 3705 = 14820 cm
3 Volume of water in Tank N at first = 14820 cm
3 Volume of water in Tank P at first
= 19 x 15 x 17
= 4845 cm
3 Total volume of water in Tank N and Tank P
= 14820 + 4845
= 19665 cm
3 Final volume of water in Tank N after 513 cm
3 of water overflowed
= 19665 - 513
= 19152 cm
3 Base area of Tank N
= 24 x 19
= 456 cm
2 Height of Tank N
= 19152 ÷ 456
= 42 cm
Answer(s): (a) 14820 cm
2 ; (b) 42 cm