The figure shows the amount of water in two rectangular tanks, G and H, at first. Pierre poured ¹₄ of the water from G into H to fill it to the top, without overflowing.

1. How much water was there in Tank G at first?
2. Pierre then poured all the water from Tank H into Tank G. 4864 cm³ of water overflowed from Tank G. What was the height of Tank G?

(a)
Volume of water to fill Tank H
= 16 x 14 x 13
= 2912 cm<sup>3

1</sup>₄ of volume of water in Tank G at first = 2912 cm^3  
4₄ of volume of water in Tank G at first = 4 x 2912 = 11648 cm³

Volume of water in Tank G at first = 11648 cm³

Volume of water in Tank H at first
= 16 x 14 x 16
= 3584 cm³

Total volume of water in Tank G and Tank H 
= 11648 + 3584
= 15232 cm³

Final volume of water in Tank G after 4864 cm³ of water overflowed
= 15232 - 4864
= 10368 cm³

Base area of Tank G
= 18 x 16
= 288 cm²

Height of Tank G
= 10368 ÷ 288 
= 36 cm

Answer(s): (a) 11648 cm² ; (b) 36 cm