The figure shows the amount of water in two rectangular tanks, J and K, at first. Warren poured
14 of the water from J into K to fill it to the top, without overflowing.
- How much water was there in Tank J at first?
- Warren then poured all the water from Tank K into Tank J. 8880 cm3 of water overflowed from Tank J. What was the height of Tank J?
(a)
Volume of water to fill Tank K
= 20 x 17 x 16
= 5440 cm
3
14 of volume of water in Tank J at first = 5440 cm
3
44 of volume of water in Tank J at first = 4 x 5440 = 21760 cm
3 Volume of water in Tank J at first = 21760 cm
3 Volume of water in Tank K at first
= 20 x 17 x 20
= 6800 cm
3 Total volume of water in Tank J and Tank K
= 21760 + 6800
= 28560 cm
3 Final volume of water in Tank J after 8880 cm
3 of water overflowed
= 28560 - 8880
= 19680 cm
3 Base area of Tank J
= 24 x 20
= 480 cm
2 Height of Tank J
= 19680 ÷ 480
= 41 cm
Answer(s): (a) 21760 cm
2 ; (b) 41 cm