The figure shows the amount of water in two rectangular tanks, H and J, at first. Fred poured
14 of the water from H into J to fill it to the top, without overflowing.
- How much water was there in Tank H at first?
- Fred then poured all the water from Tank J into Tank H. 5406 cm3 of water overflowed from Tank H. What was the height of Tank H?
(a)
Volume of water to fill Tank J
= 17 x 15 x 14
= 3570 cm
3
14 of volume of water in Tank H at first = 3570 cm
3
44 of volume of water in Tank H at first = 4 x 3570 = 14280 cm
3 Volume of water in Tank H at first = 14280 cm
3 Volume of water in Tank J at first
= 17 x 15 x 18
= 4590 cm
3 Total volume of water in Tank H and Tank J
= 14280 + 4590
= 18870 cm
3 Final volume of water in Tank H after 5406 cm
3 of water overflowed
= 18870 - 5406
= 13464 cm
3 Base area of Tank H
= 22 x 17
= 374 cm
2 Height of Tank H
= 13464 ÷ 374
= 36 cm
Answer(s): (a) 14280 cm
2 ; (b) 36 cm