The figure shows the amount of water in two rectangular tanks, D and E, at first. Carl poured
15 of the water from D into E to fill it to the top, without overflowing.
- How much water was there in Tank D at first?
- Carl then poured all the water from Tank E into Tank D. 3840 cm3 of water overflowed from Tank D. What was the height of Tank D?
(a)
Volume of water to fill Tank E
= 15 x 13 x 15
= 2925 cm
3
15 of volume of water in Tank D at first = 2925 cm
3
55 of volume of water in Tank D at first = 5 x 2925 = 14625 cm
3 Volume of water in Tank D at first = 14625 cm
3 Volume of water in Tank E at first
= 15 x 13 x 17
= 3315 cm
3 Total volume of water in Tank D and Tank E
= 14625 + 3315
= 17940 cm
3 Final volume of water in Tank D after 3840 cm
3 of water overflowed
= 17940 - 3840
= 14100 cm
3 Base area of Tank D
= 20 x 15
= 300 cm
2 Height of Tank D
= 14100 ÷ 300
= 47 cm
Answer(s): (a) 14625 cm
2 ; (b) 47 cm