The figure shows the amount of water in two rectangular tanks, P and Q, at first. Michael poured ¹₅ of the water from P into Q to fill it to the top, without overflowing.

1. How much water was there in Tank P at first?
2. Michael then poured all the water from Tank Q into Tank P. 5248 cm³ of water overflowed from Tank P. What was the height of Tank P?

(a)
Volume of water to fill Tank Q
= 16 x 14 x 15
= 3360 cm<sup>3

1</sup>₅ of volume of water in Tank P at first = 3360 cm^3  
5₅ of volume of water in Tank P at first = 5 x 3360 = 16800 cm³

Volume of water in Tank P at first = 16800 cm³

Volume of water in Tank Q at first
= 16 x 14 x 17
= 3808 cm³

Total volume of water in Tank P and Tank Q 
= 16800 + 3808
= 20608 cm³

Final volume of water in Tank P after 5248 cm³ of water overflowed
= 20608 - 5248
= 15360 cm³

Base area of Tank P
= 20 x 16
= 320 cm²

Height of Tank P
= 15360 ÷ 320 
= 48 cm

Answer(s): (a) 16800 cm² ; (b) 48 cm