The figure shows the amount of water in two rectangular tanks, H and J, at first. Henry poured
15 of the water from H into J to fill it to the top, without overflowing.
- How much water was there in Tank H at first?
- Henry then poured all the water from Tank J into Tank H. 13860 cm3 of water overflowed from Tank H. What was the height of Tank H?
(a)
Volume of water to fill Tank J
= 18 x 16 x 16
= 4608 cm
3
15 of volume of water in Tank H at first = 4608 cm
3
55 of volume of water in Tank H at first = 5 x 4608 = 23040 cm
3 Volume of water in Tank H at first = 23040 cm
3 Volume of water in Tank J at first
= 18 x 16 x 19
= 5472 cm
3 Total volume of water in Tank H and Tank J
= 23040 + 5472
= 28512 cm
3 Final volume of water in Tank H after 13860 cm
3 of water overflowed
= 28512 - 13860
= 14652 cm
3 Base area of Tank H
= 22 x 18
= 396 cm
2 Height of Tank H
= 14652 ÷ 396
= 37 cm
Answer(s): (a) 23040 cm
2 ; (b) 37 cm