The figure shows the amount of water in two rectangular tanks, N and P, at first. Albert poured
14 of the water from N into P to fill it to the top, without overflowing.
- How much water was there in Tank N at first?
- Albert then poured all the water from Tank P into Tank N. 252 cm3 of water overflowed from Tank N. What was the height of Tank N?
(a)
Volume of water to fill Tank P
= 14 x 12 x 12
= 2016 cm
3
14 of volume of water in Tank N at first = 2016 cm
3
44 of volume of water in Tank N at first = 4 x 2016 = 8064 cm
3 Volume of water in Tank N at first = 8064 cm
3 Volume of water in Tank P at first
= 14 x 12 x 15
= 2520 cm
3 Total volume of water in Tank N and Tank P
= 8064 + 2520
= 10584 cm
3 Final volume of water in Tank N after 252 cm
3 of water overflowed
= 10584 - 252
= 10332 cm
3 Base area of Tank N
= 18 x 14
= 252 cm
2 Height of Tank N
= 10332 ÷ 252
= 41 cm
Answer(s): (a) 8064 cm
2 ; (b) 41 cm