The figure shows the amount of water in two rectangular tanks, N and P, at first. Perry poured
14 of the water from N into P to fill it to the top, without overflowing.
- How much water was there in Tank N at first?
- Perry then poured all the water from Tank P into Tank N. 1692 cm3 of water overflowed from Tank N. What was the height of Tank N?
(a)
Volume of water to fill Tank P
= 18 x 14 x 13
= 3276 cm
3
14 of volume of water in Tank N at first = 3276 cm
3
44 of volume of water in Tank N at first = 4 x 3276 = 13104 cm
3 Volume of water in Tank N at first = 13104 cm
3 Volume of water in Tank P at first
= 18 x 14 x 16
= 4032 cm
3 Total volume of water in Tank N and Tank P
= 13104 + 4032
= 17136 cm
3 Final volume of water in Tank N after 1692 cm
3 of water overflowed
= 17136 - 1692
= 15444 cm
3 Base area of Tank N
= 22 x 18
= 396 cm
2 Height of Tank N
= 15444 ÷ 396
= 39 cm
Answer(s): (a) 13104 cm
2 ; (b) 39 cm