The figure shows the amount of water in two rectangular tanks, L and M, at first. Zane poured
13 of the water from L into M to fill it to the top, without overflowing.
- How much water was there in Tank L at first?
- Zane then poured all the water from Tank M into Tank L. 1056 cm3 of water overflowed from Tank L. What was the height of Tank L?
(a)
Volume of water to fill Tank M
= 16 x 12 x 14
= 2688 cm
3
13 of volume of water in Tank L at first = 2688 cm
3
33 of volume of water in Tank L at first = 3 x 2688 = 8064 cm
3 Volume of water in Tank L at first = 8064 cm
3 Volume of water in Tank M at first
= 16 x 12 x 16
= 3072 cm
3 Total volume of water in Tank L and Tank M
= 8064 + 3072
= 11136 cm
3 Final volume of water in Tank L after 1056 cm
3 of water overflowed
= 11136 - 1056
= 10080 cm
3 Base area of Tank L
= 18 x 16
= 288 cm
2 Height of Tank L
= 10080 ÷ 288
= 35 cm
Answer(s): (a) 8064 cm
2 ; (b) 35 cm