The figure shows the amount of water in two rectangular tanks, S and T, at first. Ben poured
14 of the water from S into T to fill it to the top, without overflowing.
- How much water was there in Tank S at first?
- Ben then poured all the water from Tank T into Tank S. 2064 cm3 of water overflowed from Tank S. What was the height of Tank S?
(a)
Volume of water to fill Tank T
= 16 x 13 x 14
= 2912 cm
3
14 of volume of water in Tank S at first = 2912 cm
3
44 of volume of water in Tank S at first = 4 x 2912 = 11648 cm
3 Volume of water in Tank S at first = 11648 cm
3 Volume of water in Tank T at first
= 16 x 13 x 17
= 3536 cm
3 Total volume of water in Tank S and Tank T
= 11648 + 3536
= 15184 cm
3 Final volume of water in Tank S after 2064 cm
3 of water overflowed
= 15184 - 2064
= 13120 cm
3 Base area of Tank S
= 20 x 16
= 320 cm
2 Height of Tank S
= 13120 ÷ 320
= 41 cm
Answer(s): (a) 11648 cm
2 ; (b) 41 cm