The figure shows the amount of water in two rectangular tanks, S and T, at first. Charlie poured
14 of the water from S into T to fill it to the top, without overflowing.
- How much water was there in Tank S at first?
- Charlie then poured all the water from Tank T into Tank S. 5940 cm3 of water overflowed from Tank S. What was the height of Tank S?
(a)
Volume of water to fill Tank T
= 18 x 15 x 16
= 4320 cm
3
14 of volume of water in Tank S at first = 4320 cm
3
44 of volume of water in Tank S at first = 4 x 4320 = 17280 cm
3 Volume of water in Tank S at first = 17280 cm
3 Volume of water in Tank T at first
= 18 x 15 x 18
= 4860 cm
3 Total volume of water in Tank S and Tank T
= 17280 + 4860
= 22140 cm
3 Final volume of water in Tank S after 5940 cm
3 of water overflowed
= 22140 - 5940
= 16200 cm
3 Base area of Tank S
= 20 x 18
= 360 cm
2 Height of Tank S
= 16200 ÷ 360
= 45 cm
Answer(s): (a) 17280 cm
2 ; (b) 45 cm