The figure shows the amount of water in two rectangular tanks, V and W, at first. Paul poured
14 of the water from V into W to fill it to the top, without overflowing.
- How much water was there in Tank V at first?
- Paul then poured all the water from Tank W into Tank V. 18832 cm3 of water overflowed from Tank V. What was the height of Tank V?
(a)
Volume of water to fill Tank W
= 22 x 20 x 19
= 8360 cm
3
14 of volume of water in Tank V at first = 8360 cm
3
44 of volume of water in Tank V at first = 4 x 8360 = 33440 cm
3 Volume of water in Tank V at first = 33440 cm
3 Volume of water in Tank W at first
= 22 x 20 x 22
= 9680 cm
3 Total volume of water in Tank V and Tank W
= 33440 + 9680
= 43120 cm
3 Final volume of water in Tank V after 18832 cm
3 of water overflowed
= 43120 - 18832
= 24288 cm
3 Base area of Tank V
= 24 x 22
= 528 cm
2 Height of Tank V
= 24288 ÷ 528
= 46 cm
Answer(s): (a) 33440 cm
2 ; (b) 46 cm