The figure shows the amount of water in two rectangular tanks, G and H, at first. Peter poured ¹₃ of the water from G into H to fill it to the top, without overflowing.

1. How much water was there in Tank G at first?
2. Peter then poured all the water from Tank H into Tank G. 2888 cm³ of water overflowed from Tank G. What was the height of Tank G?

(a)
Volume of water to fill Tank H
= 19 x 16 x 16
= 4864 cm<sup>3

1</sup>₃ of volume of water in Tank G at first = 4864 cm^3  
3₃ of volume of water in Tank G at first = 3 x 4864 = 14592 cm³

Volume of water in Tank G at first = 14592 cm³

Volume of water in Tank H at first
= 19 x 16 x 20
= 6080 cm³

Total volume of water in Tank G and Tank H 
= 14592 + 6080
= 20672 cm³

Final volume of water in Tank G after 2888 cm³ of water overflowed
= 20672 - 2888
= 17784 cm³

Base area of Tank G
= 24 x 19
= 456 cm²

Height of Tank G
= 17784 ÷ 456 
= 39 cm

Answer(s): (a) 14592 cm² ; (b) 39 cm