PSLE A company offered 100 water heaters at 10% discount during a 7-day sale. The line graph shows the number of water heaters left unsold at the end of each day.
- On which day was the most number of water heaters sold? Give your answer in this format. (Eg Day 1)
- What percentage of the 100 water heaters were sold in the first five days of the sale?
- During the sale, the discounted price of the water heaters was $54. After the sale, the remaining water heaters were sold without discount. What was the total amount of money collected from selling all 100 water heaters?
(a)
The steepest line is from Day 1 to Day 2.
On Day
2, the most number of water heaters was sold.
(b)
Number of water heaters that were left at Day
5 = 45 Number of water heaters that were sold for the first five days = 100 - 45 = 55 Percentage of water heaters that were sold for the first five days
=
55100 x 100%
= 55%
(c)
Number of water heaters that were left at the end of the sale = 30
Number of water heaters that were sold during the sale
= 100 - 30
= 70
Total amount that collected from the water heaters sold
= 70 x 54
= $3780
Price of each water heater after 10% discount
= 100% - 10%
= 90%
90% of the price = 54
1% of the price = 54 ÷ 90 = 0.6
100% of the price = 100 x 0.6 = 60
Amount collected from selling the remaining water heaters
= 30 x 60
= $1800
Total amount collected from selling all the 100 water heaters
= 3780 + 1800
= $5580
Answer(s): (a) Day
2; (b) 55%; (c) $5580