PSLE There was a total of 26010 cm
3 of water in rectangular tanks P and Q at first. The height of the water level in tank Q was 5 cm above that of tank P.
- Find the height of the water level in tank P.
- Kylie poured 6660 cm3 of water out of tank Q. Tank Q was then half filled with water. What was the height of tank Q?
(a)
Volume of water in Tank Q with a height of 5 cm
= 37 x 30 x 5
= 5550 cm
3 Volume of water in both tanks excluding the water that is 5 cm above that of Tank P
= 26010 - 5550
= 20460 cm
3 Base area of Tank P
= 30 x 25
= 750 cm
2 Base area of Tank Q
= 37 x 30
= 1110 cm
2 Combined base areas of both tanks
= 750 + 1110
= 1860 cm
2 Height of water in Tank P
= 20460 ÷ 1860
= 11 cm
(b)
Decrease in the height of Tank Q after some water was poured out
= 6660 ÷ 1110
= 6 cm
Original height of water before some was poured out
= 11 + 5
= 16 cm
Height of water after some was poured out
= 16 - 6
= 10 cm
Height of Tank P
= 2 x 10
= 20 cm
Answer(s): (a) 11 cm; (b) 20 cm