PSLE There was a total of 14826 cm
3 of water in rectangular tanks S and T at first. The height of the water level in tank T was 4 cm above that of tank S.
- Find the height of the water level in tank S.
- Usha poured 3276 cm3 of water out of tank T. Tank T was then half filled with water. What was the height of tank T?
(a)
Volume of water in Tank T with a height of 4 cm
= 26 x 21 x 4
= 2184 cm
3 Volume of water in both tanks excluding the water that is 4 cm above that of Tank S
= 14826 - 2184
= 12642 cm
3 Base area of Tank S
= 21 x 17
= 357 cm
2 Base area of Tank T
= 26 x 21
= 546 cm
2 Combined base areas of both tanks
= 357 + 546
= 903 cm
2 Height of water in Tank S
= 12642 ÷ 903
= 14 cm
(b)
Decrease in the height of Tank T after some water was poured out
= 3276 ÷ 546
= 6 cm
Original height of water before some was poured out
= 14 + 4
= 18 cm
Height of water after some was poured out
= 18 - 6
= 12 cm
Height of Tank S
= 2 x 12
= 24 cm
Answer(s): (a) 14 cm; (b) 24 cm