PSLE Luke kept pens in boxes M and N. Box M contained four times as many pens as box N. In box M,
13 of the pens were green pens. In box N,
12 of the pens were green pens. What fraction of Luke's pens were green pens?
Box M |
Box N |
Total |
4x2x3 |
1x2x3 |
5x2x3 |
G |
Not green |
G |
Not green |
|
1x8 |
2x8 |
1x1x3 |
1x1x3 |
|
8 u |
16 u |
3 u |
3 u |
30 u |
LCM of 3 and 8 is 24.
Number of green pens
= 8 u + 3 u
= 11 u
Total number of pens = 30 u
Fraction of Luke's pens that were green =
1130 Answer(s):
1130