PSLE David kept pens in boxes M and N. Box M contained thrice as many pens as box N. In box M,
13 of the pens were blue pens. In box N,
12 of the pens were blue pens. What fraction of David's pens were blue pens?
Box M |
Box N |
Total |
3x2x1 |
1x2x1 |
4x2x1 |
B |
Not blue |
B |
Not blue |
|
1x2 |
2x2 |
1x1x1 |
1x1x1 |
|
2 u |
4 u |
1 u |
1 u |
8 u |
LCM of 3 and 6 is 6.
Number of blue pens
= 2 u + 1 u
= 3 u
Total number of pens = 8 u
Fraction of David's pens that were blue =
38 Answer(s):
38