In a tuckshop,
49 of the students wore caps. After 64 students who wore caps entered the tuckshop, the percentage of students who wore caps increased to 80%. How many students in the tuckshop did not wear caps?
|
Wore caps |
Did not wear caps |
Before |
4x1 = 4 u |
5x1 = 5 u |
Change |
+ 64 |
|
After |
4x5 = 20 u |
1x5 = 5 u |
80% =
80100 =
45The number of students who did not wear caps remains unchanged. LCM of 5 and 1 is 5.
Number of students who wore caps and left
= 20 u - 4 u
= 16 u
16 u = 64
1 u = 64 ÷ 16 = 4
Number of students who did not wear caps
= 5 u
= 5 x 4
= 20
Answer(s): 20