In a tuckshop,
17 of the children wore sweaters. After 207 children who wore sweaters entered the tuckshop, the percentage of children who wore sweaters increased to 80%. How many children in the tuckshop did not wear sweaters?
|
Wore sweaters |
Did not wear sweaters |
Before |
1x1 = 1 u |
6x1 = 6 u |
Change |
+ 207 |
|
After |
4x6 = 24 u |
1x6 = 6 u |
80% =
80100 =
45The number of children who did not wear sweaters remains unchanged. LCM of 6 and 1 is 6.
Number of children who wore sweaters and left
= 24 u - 1 u
= 23 u
23 u = 207
1 u = 207 ÷ 23 = 9
Number of children who did not wear sweaters
= 6 u
= 6 x 9
= 54
Answer(s): 54