In a tuckshop,
56 of the students wore sweaters. After 21 students who wore sweaters left the tuckshop, the percentage of students who wore sweaters decreased to 60%. How many students in the tuckshop did not wear sweaters?
|
Wore sweaters |
Did not wear sweaters |
Before |
5x2 = 10 u |
1x2 = 2 u |
Change |
- 21 |
|
After |
3x1 = 3 u |
2x1 = 2 u |
60% =
60100 =
35The number of students who did not wear sweaters remains unchanged. LCM of 1 and 2 is 2.
Number of students who wore sweaters and left
= 10 u - 3 u
= 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of students who did not wear sweaters
= 2 u
= 2 x 3
= 6
Answer(s): 6