In a basketball court,
38 of the children wore sweaters. After 462 children who wore sweaters entered the basketball court, the percentage of children who wore sweaters increased to 90%. How many children in the basketball court did not wear sweaters?
| |
Wore sweaters |
Did not wear sweaters |
| Before |
3x1 =
3 u |
5x1 =
5 u |
| Change |
+ 462 |
|
| After |
9x5 =
45 u |
1x5 =
5 u |
90% =
90100 =
910The number of children who did not wear sweaters remains unchanged. LCM of 5 and 1 is 5.
Number of children who wore sweaters and left
= 45 u - 3 u
= 42 u
42 u = 462
1 u = 462 ÷ 42 = 11
Number of children who did not wear sweaters
= 5 u
= 5 x 11
= 55
Answer(s): 55
