In a tuckshop,
38 of the students wore ties. After 136 students who wore ties entered the tuckshop, the percentage of students who wore ties increased to 80%. How many students in the tuckshop did not wear ties?
|
Wore ties |
Did not wear ties |
Before |
3x1 = 3 u |
5x1 = 5 u |
Change |
+ 136 |
|
After |
4x5 = 20 u |
1x5 = 5 u |
80% =
80100 =
45The number of students who did not wear ties remains unchanged. LCM of 5 and 1 is 5.
Number of students who wore ties and left
= 20 u - 3 u
= 17 u
17 u = 136
1 u = 136 ÷ 17 = 8
Number of students who did not wear ties
= 5 u
= 5 x 8
= 40
Answer(s): 40