In a tuckshop,
49 of the girls wore sweaters. After 192 girls who wore sweaters entered the tuckshop, the percentage of girls who wore sweaters increased to 80%. How many girls in the tuckshop did not wear sweaters?
|
Wore sweaters |
Did not wear sweaters |
Before |
4x1 = 4 u |
5x1 = 5 u |
Change |
+ 192 |
|
After |
4x5 = 20 u |
1x5 = 5 u |
80% =
80100 =
45The number of girls who did not wear sweaters remains unchanged. LCM of 5 and 1 is 5.
Number of girls who wore sweaters and left
= 20 u - 4 u
= 16 u
16 u = 192
1 u = 192 ÷ 16 = 12
Number of girls who did not wear sweaters
= 5 u
= 5 x 12
= 60
Answer(s): 60