At a school, there were 60 boys from Club L and 30% less boys from Club M. Some boys joined Club M and the ratio of the number of boys from Club L to the number of boys from Club M became 6 : 5. How many boys joined Club M?
| |
Club L |
Club M |
| Before |
60 |
42 |
| Change |
|
+ ? |
| After |
6 u |
5 u |
Number of boys from Club M at first in percent
= 100% - 30%
= 70%
Number of boys from Club M at first
= 70% x 60
=
70100 x 60
= 42
Number of boys in Club L remains unchanged.
6 u = 60
1 u = 60 ÷ 6 = 10
Number of boys from Club M in the end
= 5 u
= 5 x 10
= 50
Number of boys joined Club M
= 50 - 42
= 8
Answer(s): 8
