At a school, there were 40 children from Club Z and 10% more children from Club A. Some children from Club A left and the ratio of the number of children from Club Z to the number of children from Club A became 5 : 2. How many children from Club A left?
| |
Club Z |
Club A |
| Before |
40 |
44 |
| Change |
|
- ? |
| After |
5 u |
2 u |
Number of children from Club A at first in percent
= 100% + 10%
= 110%
Number of children from Club A at first
= 110% x 40
=
110100 x 40
= 44
Number of children in Club Z remains unchanged.
5 u = 40
1 u = 40 ÷ 5 = 8
Number of children from Club A in the end
= 2 u
= 2 x 8
= 16
Number of children from Club A who left
= 44 - 16
= 28
Answer(s): 28
