At a school, there were 20 children from Club B and 40% more children from Club C. Some children from Club C left and the ratio of the number of children from Club B to the number of children from Club C became 5 : 3. How many children from Club C left?
| |
Club B |
Club C |
| Before |
20 |
28 |
| Change |
|
- ? |
| After |
5 u |
3 u |
Number of children from Club C at first in percent
= 100% + 40%
= 140%
Number of children from Club C at first
= 140% x 20
=
140100 x 20
= 28
Number of children in Club B remains unchanged.
5 u = 20
1 u = 20 ÷ 5 = 4
Number of children from Club C in the end
= 3 u
= 3 x 4
= 12
Number of children from Club C who left
= 28 - 12
= 16
Answer(s): 16
