At a school, there were 40 children from Club L and 30% more children from Club M. Some children from Club M left and the ratio of the number of children from Club L to the number of children from Club M became 5 : 2. How many children from Club M left?
|
Club L |
Club M |
Before |
40 |
52 |
Change |
|
- ? |
After |
5 u |
2 u |
Number of children from Club M at first in percent
= 100% + 30%
= 130%
Number of children from Club M at first
= 130% x 40
=
130100 x 40
= 52
Number of children in Club L remains unchanged.
5 u = 40
1 u = 40 ÷ 5 = 8
Number of children from Club M in the end
= 2 u
= 2 x 8
= 16
Number of children from Club M who left
= 52 - 16
= 36
Answer(s): 36