At a school, there were 60 pupils from Club M and 20% more pupils from Club N. Some pupils from Club N left and the ratio of the number of pupils from Club M to the number of pupils from Club N became 5 : 2. How many pupils from Club N left?
| |
Club M |
Club N |
| Before |
60 |
72 |
| Change |
|
- ? |
| After |
5 u |
2 u |
Number of pupils from Club N at first in percent
= 100% + 20%
= 120%
Number of pupils from Club N at first
= 120% x 60
=
120100 x 60
= 72
Number of pupils in Club M remains unchanged.
5 u = 60
1 u = 60 ÷ 5 = 12
Number of pupils from Club N in the end
= 2 u
= 2 x 12
= 24
Number of pupils from Club N who left
= 72 - 24
= 48
Answer(s): 48
