At a school, there were 60 children from Club E and 20% more children from Club F. Some children from Club F left and the ratio of the number of children from Club E to the number of children from Club F became 5 : 4. How many children from Club F left?
|
Club E |
Club F |
Before |
60 |
72 |
Change |
|
- ? |
After |
5 u |
4 u |
Number of children from Club F at first in percent
= 100% + 20%
= 120%
Number of children from Club F at first
= 120% x 60
=
120100 x 60
= 72
Number of children in Club E remains unchanged.
5 u = 60
1 u = 60 ÷ 5 = 12
Number of children from Club F in the end
= 4 u
= 4 x 12
= 48
Number of children from Club F who left
= 72 - 48
= 24
Answer(s): 24