At a school, there were 60 children from Club B and 30% less children from Club C. Some children joined Club C and the ratio of the number of children from Club B to the number of children from Club C became 5 : 4. How many children joined Club C?
| |
Club B |
Club C |
| Before |
60 |
42 |
| Change |
|
+ ? |
| After |
5 u |
4 u |
Number of children from Club C at first in percent
= 100% - 30%
= 70%
Number of children from Club C at first
= 70% x 60
=
70100 x 60
= 42
Number of children in Club B remains unchanged.
5 u = 60
1 u = 60 ÷ 5 = 12
Number of children from Club C in the end
= 4 u
= 4 x 12
= 48
Number of children joined Club C
= 48 - 42
= 6
Answer(s): 6
