At a school, there were 50 children from Club L and 10% more children from Club M. Some children from Club M left and the ratio of the number of children from Club L to the number of children from Club M became 5 : 3. How many children from Club M left?
| |
Club L |
Club M |
| Before |
50 |
55 |
| Change |
|
- ? |
| After |
5 u |
3 u |
Number of children from Club M at first in percent
= 100% + 10%
= 110%
Number of children from Club M at first
= 110% x 50
=
110100 x 50
= 55
Number of children in Club L remains unchanged.
5 u = 50
1 u = 50 ÷ 5 = 10
Number of children from Club M in the end
= 3 u
= 3 x 10
= 30
Number of children from Club M who left
= 55 - 30
= 25
Answer(s): 25
