At a school, there were 20 children from Club L and 25% more children from Club M. Some children from Club M left and the ratio of the number of children from Club L to the number of children from Club M became 4 : 3. How many children from Club M left?
| |
Club L |
Club M |
| Before |
20 |
25 |
| Change |
|
- ? |
| After |
4 u |
3 u |
Number of children from Club M at first in percent
= 100% + 25%
= 125%
Number of children from Club M at first
= 125% x 20
=
125100 x 20
= 25
Number of children in Club L remains unchanged.
4 u = 20
1 u = 20 ÷ 4 = 5
Number of children from Club M in the end
= 3 u
= 3 x 5
= 15
Number of children from Club M who left
= 25 - 15
= 10
Answer(s): 10
