At a school, there were 55 boys from Club M and 40% more boys from Club N. Some boys from Club N left and the ratio of the number of boys from Club M to the number of boys from Club N became 5 : 3. How many boys from Club N left?
| |
Club M |
Club N |
| Before |
55 |
77 |
| Change |
|
- ? |
| After |
5 u |
3 u |
Number of boys from Club N at first in percent
= 100% + 40%
= 140%
Number of boys from Club N at first
= 140% x 55
=
140100 x 55
= 77
Number of boys in Club M remains unchanged.
5 u = 55
1 u = 55 ÷ 5 = 11
Number of boys from Club N in the end
= 3 u
= 3 x 11
= 33
Number of boys from Club N who left
= 77 - 33
= 44
Answer(s): 44
