At a school, there were 50 children from Club Y and 40% more children from Club Z. Some children from Club Z left and the ratio of the number of children from Club Y to the number of children from Club Z became 5 : 3. How many children from Club Z left?
| |
Club Y |
Club Z |
| Before |
50 |
70 |
| Change |
|
- ? |
| After |
5 u |
3 u |
Number of children from Club Z at first in percent
= 100% + 40%
= 140%
Number of children from Club Z at first
= 140% x 50
=
140100 x 50
= 70
Number of children in Club Y remains unchanged.
5 u = 50
1 u = 50 ÷ 5 = 10
Number of children from Club Z in the end
= 3 u
= 3 x 10
= 30
Number of children from Club Z who left
= 70 - 30
= 40
Answer(s): 40
