There were some pens in Packet G and Packet H. After Lee transferred
15 of the pens from Packet G to Packet H, the ratio of the number of pens in Packet G to that in Packet H changed to 1 : 7. Find the ratio of the numbers of pens in Packet H to the number of pens in Packet G at first.
|
Packet G |
Packet H |
Before |
5x1 = 5 u |
27 u |
Change |
- 1x1 = - 1 u |
+ 1 u |
After |
4x1 = 4 u |
|
Comparing Packet G and Packet H in the end |
1x4 = 4 u |
7x4 = 28 u |
The number of pens in Packet G in the end is repeated. Make the number of pens in Packet G in the end the same. LCM of 4 and 1 is 4.
At first
Packet H : Packet G
27: 5
Answer(s): 27: 5