There were some pens in Box E and Box F. After Tim transferred
35 of the pens from Box E to Box F, the ratio of the number of pens in Box E to that in Box F changed to 1 : 7. Find the ratio of the numbers of pens in Box E to the number of pens in Box F at first.
| |
Box E |
Box F |
| Before |
5x1 =
5 u |
11 u |
| Change |
- 3x1 =
- 3 u |
+ 3 u |
| After |
2x1 =
2 u |
|
Comparing Box E and
Box F in the end |
1x2 =
2 u |
7x2 =
14 u |
The number of pens in Box E in the end is repeated. Make the number of pens in Box E in the end the same. LCM of 2 and 1 is 2.
At first
Box E : Box F
5 : 11
Answer(s): 5 : 11
