There were some erasers in Packet T and Packet U. After Cole transferred
15 of the erasers from Packet T to Packet U, the ratio of the number of erasers in Packet T to that in Packet U changed to 3 : 5. Find the ratio of the numbers of erasers in Packet T to the number of erasers in Packet U at first.
|
Packet T |
Packet U |
Before |
5x3 = 15 u |
17 u |
Change |
- 1x3 = - 3 u |
+ 3 u |
After |
4x3 = 12 u |
|
Comparing Packet T and Packet U in the end |
3x4 = 12 u |
5x4 = 20 u |
The number of erasers in Packet T in the end is repeated. Make the number of erasers in Packet T in the end the same. LCM of 4 and 3 is 12.
At first
Packet T : Packet U
15 : 17
Answer(s): 15 : 17