There were some beads in Box G and Box H. After Andy transferred
14 of the beads from Box G to Box H, the ratio of the number of beads in Box G to that in Box H changed to 2 : 9. Find the ratio of the numbers of beads in Box H to the number of beads in Box G at first.
| |
Box G |
Box H |
| Before |
4x2 =
8 u |
25 u |
| Change |
- 1x2 =
- 2 u |
+ 2 u |
| After |
3x2 =
6 u |
|
Comparing Box G and
Box H in the end |
2x3 =
6 u |
9x3 =
27 u |
The number of beads in Box G in the end is repeated. Make the number of beads in Box G in the end the same. LCM of 3 and 2 is 6.
At first
Box H : Box G
25: 8
Answer(s): 25: 8
