There were some pens in Packet A and Packet B. After Henry transferred
35 of the pens from Packet A to Packet B, the ratio of the number of pens in Packet A to that in Packet B changed to 3 : 8. Find the ratio of the numbers of pens in Packet B to the number of pens in Packet A at first.
|
Packet A |
Packet B |
Before |
5x3 = 15 u |
7 u |
Change |
- 3x3 = - 9 u |
+ 9 u |
After |
2x3 = 6 u |
|
Comparing Packet A and Packet B in the end |
3x2 = 6 u |
8x2 = 16 u |
The number of pens in Packet A in the end is repeated. Make the number of pens in Packet A in the end the same. LCM of 2 and 3 is 6.
At first
Packet B : Packet A
7: 15
Answer(s): 7: 15