There were some erasers in Bag H and Bag J. After Ivan transferred
15 of the erasers from Bag H to Bag J, the ratio of the number of erasers in Bag H to that in Bag J changed to 1 : 5. Find the ratio of the numbers of erasers in Bag J to the number of erasers in Bag H at first.
|
Bag H |
Bag J |
Before |
5x1 = 5 u |
19 u |
Change |
- 1x1 = - 1 u |
+ 1 u |
After |
4x1 = 4 u |
|
Comparing Bag H and Bag J in the end |
1x4 = 4 u |
5x4 = 20 u |
The number of erasers in Bag H in the end is repeated. Make the number of erasers in Bag H in the end the same. LCM of 4 and 1 is 4.
At first
Bag J : Bag H
19: 5
Answer(s): 19: 5