There were some coins in Box H and Box J. After Oliver transferred
25 of the coins from Box H to Box J, the ratio of the number of coins in Box H to that in Box J changed to 1 : 7. Find the ratio of the numbers of coins in Box H to the number of coins in Box J at first.
|
Box H |
Box J |
Before |
5x1 = 5 u |
19 u |
Change |
- 2x1 = - 2 u |
+ 2 u |
After |
3x1 = 3 u |
|
Comparing Box H and Box J in the end |
1x3 = 3 u |
7x3 = 21 u |
The number of coins in Box H in the end is repeated. Make the number of coins in Box H in the end the same. LCM of 3 and 1 is 3.
At first
Box H : Box J
5 : 19
Answer(s): 5 : 19