There were some coins in Packet L and Packet M. After Henry transferred
35 of the coins from Packet L to Packet M, the ratio of the number of coins in Packet L to that in Packet M changed to 3 : 8. Find the ratio of the numbers of coins in Packet L to the number of coins in Packet M at first.
|
Packet L |
Packet M |
Before |
5x3 = 15 u |
7 u |
Change |
- 3x3 = - 9 u |
+ 9 u |
After |
2x3 = 6 u |
|
Comparing Packet L and Packet M in the end |
3x2 = 6 u |
8x2 = 16 u |
The number of coins in Packet L in the end is repeated. Make the number of coins in Packet L in the end the same. LCM of 2 and 3 is 6.
At first
Packet L : Packet M
15 : 7
Answer(s): 15 : 7